Wire Problem

Dec 2019
23
0
hello world
pro.PNG

I tried using the magnetic field for a wire equation * 2pir, but this didn't work. Please help!
 

topsquark

Forum Staff
Apr 2008
3,106
659
On the dance floor, baby!
You also have the contribution from the straight wire. Did you include this?

-Dan
 
Dec 2019
23
0
hello world
This is all the information given... I believe they share the same current
 
Dec 2019
23
0
hello world
okay so I calculated the magnetic field of the wire + magnetic field of loop * 2pir, but I am not getting what I want. Why?
 

topsquark

Forum Staff
Apr 2008
3,106
659
On the dance floor, baby!
I can't tell you where you went wrong if you don't tell me what you did. Please post what you have been able to do.

-Dan
 
Dec 2019
23
0
hello world
So, we know that the formula for the magnetic field produced by a wire is given by $\frac{\mu I}{2 \pi r}$. I calculated the magnetic field at the center of the wire as as $B = B_{straight wire} + B_{loop} = \frac{\mu I}{2 \pi r} * 2 \pi r + \frac{\mu I}{2 \pi r}$, but this was wrong.
 

topsquark

Forum Staff
Apr 2008
3,106
659
On the dance floor, baby!
First note that \(\displaystyle \dfrac{ \mu _0 I}{2 \pi R} \cdot 2 \pi R\) has the wrong units. It's always a good idea to check the units.

You've got some wrong formulas.
\(\displaystyle B_{wire} = \dfrac{ \mu _0 I}{2 \pi R}\)

\(\displaystyle B_{loop} = \dfrac{ \mu _0 I}{2R}\)

-Dan
 
Dec 2019
23
0
hello world
First note that \(\displaystyle \dfrac{ \mu _0 I}{2 \pi R} \cdot 2 \pi R\) has the wrong units. It's always a good idea to check the units.

You've got some wrong formulas.
\(\displaystyle B_{wire} = \dfrac{ \mu _0 I}{2 \pi R}\)

\(\displaystyle B_{loop} = \dfrac{ \mu _0 I}{2R}\)

-Dan

Could you please explain how you got the formula for $B_{loop}$?