volume flow rate

ChipB

PHF Helper
Jun 2010
2,367
292
Morristown, NJ USA
I believe that gamma = specific weight of the fluid, in N/m^3, and G = "weight flow," which is equal to mass (Kg/s) flow times g (acceleration due to gravity) in Newtons per second. In other words:

gamma = rho times g
G = "m dot" times g.
 
Jun 2014
306
0
I believe that gamma = specific weight of the fluid, in N/m^3, and G = "weight flow," which is equal to mass (Kg/s) flow times g (acceleration due to gravity) in Newtons per second. In other words:

gamma = rho times g
G = "m dot" times g.
accoding to what have u said , i have V = G/( rho (A) )

V= ( kgs^-1 / (kgms^-2)(m^2) )
= m^-3 s^-1

i gt m^-3 s^-1 instead of m^3 s^-1
 

ChipB

PHF Helper
Jun 2010
2,367
292
Morristown, NJ USA
accoding to what have u said , i have V = G/( rho (A) )

V= ( kgs^-1 / (kgms^-2)(m^2) )
= m^-3 s^-1

i gt m^-3 s^-1 instead of m^3 s^-1

1. I said that G is weight (not mass) per second, not mass times seconds. And gamma is weight (not mass) per m^3, not mass times m^3.

2. 'V' in this equation is velocity, not volume, so the units should work out to m/s.

3. The dimensional analysis is: V = (N/s)/(N/m^3 x m^2) = m/s.