Torque and forces on a rigid triangle body

ChipB

PHF Helper
Jun 2010
2,369
294
Morristown, NJ USA
I think you meant FMx=5.5, not FMy in your last post.
Yes - that's right. Thanks.

I think we're in agreement. I believe the minor differences in results are due to rounding. I do agree that if you don't care about the reaction force FMx then you only need the two equations that you have used.
 
Feb 2017
18
0
Excellent.

Thanks for all your help Chip, for good explanations and for sticking with it through such a lengthy thread. I definitely feel I know what's going on with this piece now. :)