Test

Apr 2015
1,227
356
Somerset, England
\(\displaystyle \left( {\begin{array}{*{20}{c}}
{{a_{11}}} & {{a_{12}}} \\
{{a_{21}}} & {{a_{22}}} \\
\end{array}} \right)\)


\(\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}} \)


\(\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}} \)


\(\displaystyle \sqrt {{a^2} + {b^2}} \)


\(\displaystyle \sqrt {{a^2} + {b^2}} \)

So mathml now works here, that's really useful.

not sure what's wrong with the tex version though.
 
Last edited:

topsquark

Forum Staff
Apr 2008
3,106
659
On the dance floor, baby!
\(\displaystyle \left( {\begin{array}{*{20}{c}}
{{a_{11}}} & {{a_{12}}} \\
{{a_{21}}} & {{a_{22}}} \\
\end{array}} \right)\)


\(\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}} \)


\(\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}} \)


\(\displaystyle \sqrt {{a^2} + {b^2}} \)


\(\displaystyle \sqrt {{a^2} + {b^2}} \)

So mathml now works here, that's really useful.

not sure what's wrong with the tex version though.
There isn't anything wrong with the coding, it's just that the tex tags don't work any more.

-Dan
 
Nov 2013
552
30
New Zealand
\(\displaystyle \left( {\begin{array}{*{20}{c}}
{{a_{11}}} & {{a_{12}}} \\
{{a_{21}}} & {{a_{22}}} \\
\end{array}} \right)\)


\(\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}} \)


\(\displaystyle \sum\nolimits_{n = 1}^\infty {{n^2}} \)


\(\displaystyle \sqrt {{a^2} + {b^2}} \)


\(\displaystyle \sqrt {{a^2} + {b^2}} \)

So mathml now works here, that's really useful.

not sure what's wrong with the tex version though.
testing....

\(\displaystyle \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\)