I have a problem with calculating the support reactions for a beam. Lefts side of beam has a pin connection so it takes both \(\displaystyle Fx, Fy\). Right side of the beam has a horizontal roller and it takes only \(\displaystyle Fy\) in the direction of the wall. Therefore at the pin support \(\displaystyle Fy=9kN\), but how do i figure out the reactions for X-direction? i Thought about the X-component as a tangent to the 2 point loads so \(\displaystyle 5kN/tan(21.8); 4kN/tan(21.8)\) and they give me 12,5 and 10kN respectively. I don't Know if they are correct and if they are how do they distribute to each support?
I can also think of another way of doing this and that is by making the beam horizontal and turning the roller support 68.2 degrees, then calculating the reactions which come out to 3,8kN for Ay 9,5kN to Ax
5,2kN for By and 13kN for Bx. Is either of these methods correct?