# Pulley problem

#### Cervesa

From a force diagram, $2T\sin{\theta} = mg$

The wave in your diagram has a wavelength, $\lambda = 2 \text{ m}$. If I recall correctly, speed of the wave is $v = \sqrt{\dfrac{T}{\mu}}$. You should have enough information to determine the wave's frequency.

topsquark

#### bluemouse

I got theta = 64.4 degrees, T = 64.17N, and f = 126.66 Hz... does this sound about right?

#### Cervesa

Sorry, but that's incorrect.

note that $\sin{\theta} = \dfrac{\text{opposite side}}{\text{hypotenuse}}$

#### bluemouse

$\cos{\theta} = \dfrac{1}{1.5}$
$\sin{\theta} = \dfrac{\sqrt{1.5^2-1^2}}{1.5}$