Cervesa Jan 2019 55 41 Dec 6, 2019 #2 From a force diagram, $2T\sin{\theta} = mg$ The wave in your diagram has a wavelength, $\lambda = 2 \text{ m}$. If I recall correctly, speed of the wave is $v = \sqrt{\dfrac{T}{\mu}}$. You should have enough information to determine the wave's frequency. Reactions: topsquark

From a force diagram, $2T\sin{\theta} = mg$ The wave in your diagram has a wavelength, $\lambda = 2 \text{ m}$. If I recall correctly, speed of the wave is $v = \sqrt{\dfrac{T}{\mu}}$. You should have enough information to determine the wave's frequency.

B bluemouse Dec 2019 13 0 us Dec 7, 2019 #3 I got theta = 64.4 degrees, T = 64.17N, and f = 126.66 Hz... does this sound about right?

Cervesa Jan 2019 55 41 Dec 7, 2019 #4 Sorry, but that's incorrect. note that $\sin{\theta} = \dfrac{\text{opposite side}}{\text{hypotenuse}}$

Sorry, but that's incorrect. note that $\sin{\theta} = \dfrac{\text{opposite side}}{\text{hypotenuse}}$

B bluemouse Dec 2019 13 0 us Dec 7, 2019 #5 I had cos(theta) = adj/hypotenuse = (2m/2)/(5m/2)... is this wrong?

Cervesa Jan 2019 55 41 Dec 8, 2019 #6 $\cos{\theta} = \dfrac{1}{1.5}$ $\sin{\theta} = \dfrac{\sqrt{1.5^2-1^2}}{1.5}$