Pulley problem

Dec 2019
13
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us
stuckpull.PNGPlease help! I am not sure how to start on this
 
Jan 2019
55
41
From a force diagram, $2T\sin{\theta} = mg$

equilibrium10.jpg

The wave in your diagram has a wavelength, $\lambda = 2 \text{ m}$. If I recall correctly, speed of the wave is $v = \sqrt{\dfrac{T}{\mu}}$. You should have enough information to determine the wave's frequency.
 
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Dec 2019
13
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I got theta = 64.4 degrees, T = 64.17N, and f = 126.66 Hz... does this sound about right?
 
Jan 2019
55
41
Sorry, but that's incorrect.

note that $\sin{\theta} = \dfrac{\text{opposite side}}{\text{hypotenuse}}$
 
Dec 2019
13
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I had cos(theta) = adj/hypotenuse = (2m/2)/(5m/2)... is this wrong?
 
Jan 2019
55
41
$\cos{\theta} = \dfrac{1}{1.5}$

$\sin{\theta} = \dfrac{\sqrt{1.5^2-1^2}}{1.5}$