My guess was "the same angular velocity than the Earth has" but the answer given is \(\displaystyle \omega=\sqrt{\frac{GM_E}{(R_E+h)^3}}\) where \(\displaystyle M_E\) is the mass of the earth, \(\displaystyle G\) is the universal gravitational constant and \(\displaystyle R_E\) is the radius of the Earth.

How can I reach to the answer? (Please give me the full answer if you can because my exam is tomorrow and I promise I'll try to understand the exercise). Thanks in advance.

P.S.: I suppose I have to use the formula \(\displaystyle F_g=\frac{Gm_sM_E}{R^2}\) and maybe also \(\displaystyle \omega=\frac{v}{r}\) and probably \(\displaystyle a_c=\frac{v^2}{r}\) with \(\displaystyle F_c=m_sa_c\).