A glass tube of cross-sectional area 1.0x10^-4 m^2 is partially filled with water. An oil with a density of 800kg/m^3 is slowly poured into the tube and floats on top of the water. The height of the oil above the water surface is 8cm.

A) what is the change in pressure at a depth of 10 cm below the water surface?

b) would the pressure at this depth increase or decrease if you added more oil to the tube? Why?

My work:

a) Poil = P0+pgh

Poil = 1.013e5 +800x9.8x0.08

Poil = 101927.2 Pa

Pwater = 1.013e5 + 1000x9.8x0.18

Pwater = 103064

0.18 is when I added 0.08 +0.10 because that is the depth of the water? I think.

Then I subtracted the Pwater from the Poil to get 1136.8 Pa. I don't think that is right at all b/c someone told me you only need to calculate pressure of oil??? What? Also, I don't know how would I use the cross sectional area for this question, is it just extra useless info? Sorry for the formatting.

b) Increase because more oil = greater depth = greater pressure.

A) what is the change in pressure at a depth of 10 cm below the water surface?

b) would the pressure at this depth increase or decrease if you added more oil to the tube? Why?

My work:

a) Poil = P0+pgh

Poil = 1.013e5 +800x9.8x0.08

Poil = 101927.2 Pa

Pwater = 1.013e5 + 1000x9.8x0.18

Pwater = 103064

0.18 is when I added 0.08 +0.10 because that is the depth of the water? I think.

Then I subtracted the Pwater from the Poil to get 1136.8 Pa. I don't think that is right at all b/c someone told me you only need to calculate pressure of oil??? What? Also, I don't know how would I use the cross sectional area for this question, is it just extra useless info? Sorry for the formatting.

b) Increase because more oil = greater depth = greater pressure.

Last edited: