Power Calculations

Apr 2017
48
2
Turkey
Hello everybody

Could you help me to solve this question ?

Best regards
Razi
 

Attachments

Aug 2010
434
174
Since you use the term "drag coefficient" can we assume that you know what it means? According to Wikipedia, the drag coefficient is given by \(\displaystyle c_d= \frac{2F_d}{\rho u^2A}\) where \(\displaystyle c_d\) is the drag coefficient, \(\displaystyle F_d\) is the drag force, \(\displaystyle \rho\) is the density of the fluid, u is the speed through the fluid, and A is the cross section area. You are asked for the drag force so solve for that: \(\displaystyle F_d= \frac{c_d\rho u^2A}{2}\). You are given that A= 400 square cm. and \(\displaystyle c_d= 0.6\). You will need to look up the density of air and water and calculate u, the speed of an object moving at 1000 rev/min around a circle of radius \(\displaystyle 10 sin(120^o)\).
 
Apr 2017
48
2
Turkey
Thanks Dear HallsofIvy for your help

Best regards