#### Cervesa

constant speed $\implies F_{net} = 0$

pulling force up the hill = gravitational force down the incline + friction force down the incline

#### Tinky

May I ask how to find the gravitational force down the incline and the friction force down the incline respectively? I am not sure about that.

#### Tinky

so the equation should be (6.19+9.85)(9.8)(0.91)+(6.19+9.85)(9.8)(sin(tan-1(2.5/4.75))?

#### Cervesa

first of all, what you have written is an expression, not an equation

second, you need to review the formula for determining kinetic friction