For part a ) , my ans is EI(d2y/dx2) =  Px
For part b) , my ans is EI(dy/dx) = P(x^2)/2 +c1 EIy = P(x^3)/6 +c1x +c2
at x= 0 , y = 0 , so c2 = 0 , at x = 0 , dy/dx = 0 , so c1 = 0 ,
so , EIy = P(x^3)/6 , so , EIy max occur at L=3 , so EIy max = 10(3^3) / 6 = 45 , but the ans is EIy max =46.67 , which part of my working is wrong ??
for slope at x = 2 , my ans is EI(dy/dx) = P(x^2)/2 = EI(dy/dx) = 10(2^2)/2 = 40/EI
For part b) , my ans is EI(dy/dx) = P(x^2)/2 +c1 EIy = P(x^3)/6 +c1x +c2
at x= 0 , y = 0 , so c2 = 0 , at x = 0 , dy/dx = 0 , so c1 = 0 ,
so , EIy = P(x^3)/6 , so , EIy max occur at L=3 , so EIy max = 10(3^3) / 6 = 45 , but the ans is EIy max =46.67 , which part of my working is wrong ??
for slope at x = 2 , my ans is EI(dy/dx) = P(x^2)/2 = EI(dy/dx) = 10(2^2)/2 = 40/EI
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