to calculate the work done by friction. I have that the kinetic coefficient is .09 and I know delta x and i know for the problem the other part of the eq is cos(180).I also know mass is 215 kg. and acceleration is .131
So it is Wf= Ff*1.77*cos180
In the worked out solutions my professor but the Ff as 177 but I can't figure out how he got that. Thank you.
So it is Wf= Ff*1.77*cos180
In the worked out solutions my professor but the Ff as 177 but I can't figure out how he got that. Thank you.