How to solve this

Jul 2019
6
0
Hello sir
How to solve this
The amount of work done in moving a charge of 10C from a point of 180 volts to another point of 210 volt is
1. 1800J
2. 300J
3. 3900J
4. 3000J
 

topsquark

Forum Staff
Apr 2008
2,978
631
On the dance floor, baby!
Hello sir
How to solve this
The amount of work done in moving a charge of 10C from a point of 180 volts to another point of 210 volt is
1. 1800J
2. 300J
3. 3900J
4. 3000J
\(\displaystyle W = Q \Delta V\)

So....

-Dan
 
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topsquark

Forum Staff
Apr 2008
2,978
631
On the dance floor, baby!
W=qΔv

w=10c*30v
w=300j
Good! However a quick note: The unit "volts" is represented as "V" and "Joules" is "J". Capitalization is important.

-Dan
 
Jun 2016
1,198
565
England
Naming Conventions

I have a vague recollection from somewhere that the units that are named after a person use a Capital first letter, and thus a Capital abbreviation
Thus:
V for Volts (named after Alessandro Volta),
J for Joule (James Prescott Joule),
W for Watt (James Watt),
etc.
But lower case for other units.
Thus:
m for metre,
g for gram,
etc.
 
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