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Theoretical ...

Btu / h: 136.1 x10 ^ 6

Flow Steam: 136,000 pph (I think it's pound per hour)

Ti of the steam: 312 F

To the steam: 212 F

Psi steam: 65 psi

Water flow: 3110 USGPM (us allon per minute)

Water Ti: 70 F

to water: 158 F

Psi of water: 100 psi

Area: 3800 ft ^ 2

LMTD (corrected): 148

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1. The strange thing is that our steam line can only have 14,000 kg/h of steam and according to the equation Q = m * Cp * dT, the steam flow should be above 1,000,000 lbs / h?

2. What I would like to do:

The exchanger is not always in use. When not in use, I would like to give him 530 kg of steam to heat the water. What is the flow of water needed to increase the dT of it by 3 F?

Thank you so much ,

JohnMitchell