Let’s say you have a mass that weighs 15,329 lbs. or 6,953.11 Kg and you have ten feet of fall to play with. Between the air intake of the tank and the weight, you have either one very large piston, or a series of smaller pitons. The chamber(s) of the one piston or multiple pistons shall equal 255 cubic feet. You will be using the weight to drive the piston and force the air into the pressure tank (which is already exerting 36 psi against you). You can use the 10 foot fall any way you wish. You can have the weight drop in ten 1 foot increments or 2 five foot drops, or one long 10 foot drop whichever is optimal. You could have the weight free fall for 5 or 9 feet before hitting the piston adding additional force.

I would like to know how much of the 255 cubic feet of air could you force into that pressure tank given these parameters to work with. Also I would like to know if you changed the size of the tank, say you made it half the size: 669 cubic feet and you add 1657.5 cubic feet to get your 2.47 atmospheres and 36 PSI. Would the amount of air you could force into the vessel increase, decrease or remain the same as in the previous example?