drawing a velocity time graph and displacement time graph.

Mar 2009
5
0
heres the information given its about someone walking jogging and running.

walking 900meters in 10 mins, stopped for 15 mins, walking back to the same spot at 900meters in 10mins, jogs 450meters in 3 mins, then runs 1200meters in 6 mins.

Picture0001.jpg this is what I thought a v-t graph would look like


Picture0002.jpg this is what I thought the displacement-time graph would look like

I feel like I screwed up lol.
 

topsquark

Forum Staff
Apr 2008
3,016
636
On the dance floor, baby!
heres the information given its about someone walking jogging and running.

walking 900meters in 10 mins, stopped for 15 mins, walking back to the same spot at 900meters in 10mins, jogs 450meters in 3 mins, then runs 1200meters in 6 mins.

View attachment 733 this is what I thought a v-t graph would look like


View attachment 734 this is what I thought the displacement-time graph would look like

I feel like I screwed up lol.
As I can't really see the axes, all I can say is that the displacement vs. time graph looks reasonable. For the velocity vs. time graph note that since the direction of travel is in the negative direction, the velocity is negative. (This is for the "walking back" part after stopping for 15 min.) I am assuming the other velocities were in the positive direction. The problem statement doesn't actually say.

-Dan