Is it possible to find the VA , VB and VC without ' breaking ' the beam into 2 parts ?
2. Relevant equations
3. The attempt at a solution
Here's my working , i gt
Moment about A = 10(1) VB(2) VC(4) +5(3)(4 + (3/2) ) = 0 Hence , 92.52VB 4VC= 0
moment about B = VA(2) 10VC(2) +(5)(3)(2 + (3/2) ) = 0 Hence , 42.5 + 2VA 2VC = 0
Moment about C = VA(4) 10(3) +VB(2) + (5)(3)(3/2) =0, Hence , 7.5 +4VA +2VB = 0
and sum of vertical force = VA +VB +VC = 25
Then , i solve the 4 equations using online calculator , i found that some of the values couldnt be found .
Or there's something wrong with my working ?
2. Relevant equations
3. The attempt at a solution
Here's my working , i gt
Moment about A = 10(1) VB(2) VC(4) +5(3)(4 + (3/2) ) = 0 Hence , 92.52VB 4VC= 0
moment about B = VA(2) 10VC(2) +(5)(3)(2 + (3/2) ) = 0 Hence , 42.5 + 2VA 2VC = 0
Moment about C = VA(4) 10(3) +VB(2) + (5)(3)(3/2) =0, Hence , 7.5 +4VA +2VB = 0
and sum of vertical force = VA +VB +VC = 25
Then , i solve the 4 equations using online calculator , i found that some of the values couldnt be found .
Or there's something wrong with my working ?
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