I'm just confused with the word semi-rigid. I would appreciate some help on how to go about this. Thank you

- Thread starter Jaybee1
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I'm just confused with the word semi-rigid. I would appreciate some help on how to go about this. Thank you

But the author implies tank volume change with the event. I can't help. What text did this premise?

However, just by way of interest, check this out. Pressure Cooker

Ordinary Physics gas law calculations are not accurate enough for water which is an exceptional substance.

So to begin, the initial pressure and temperature are irrelevant.

The water is heated in a semi rigid container so any steam generated will be saturated vapour confined by the liquid (which will be at the same pressure).

Effectively semi rigid means that the vessel undergoes negligable expansion, but does not pretend to be ideal.

My tables give a temperature of 417 F for a saturated water substance at 300 psi.

So there is your temperature.

To calculate the expansion % after bursting, the table gives the specific volume of the water at this temperature and pressure as 0.018896 cuft /lb and for vapour

1.5442 cuft / lb.

You would have to decide if you are going to say all the water turns to steam on release at bursting.

Then the ration of these two figures will give the expansion %

Ordinary Physics gas law calculations are not accurate enough for water which is an exceptional substance.

So to begin, the initial pressure and temperature are irrelevant.

The water is heated in a semi rigid container so any steam generated will be saturated vapour confined by the liquid (which will be at the same pressure).

Effectively semi rigid means that the vessel undergoes negligable expansion, but does not pretend to be ideal.

My tables give a temperature of 417 F for a saturated water substance at 300 psi.

So there is your temperature.

To calculate the expansion % after bursting, the table gives the specific volume of the water at this temperature and pressure as 0.018896 cuft /lb and for vapour

1.5442 cuft / lb.

You would have to decide if you are going to say all the water turns to steam on release at bursting.

Then the ration of these two figures will give the expansion %

This makes a lot sense. Thanks a lot

in other words the tank is rigid enough to hold the water (until it ruptures)

but not rigid enough to compress the water, and thus alter your calculations of increase of the volume of the water due to the temperature

Ordinary Physics gas law calculations are not accurate enough for water which is an exceptional substance.

So to begin, the initial pressure and temperature are irrelevant.

The water is heated in a semi rigid container so any steam generated will be saturated vapour confined by the liquid (which will be at the same pressure).

Effectively semi rigid means that the vessel undergoes negligable expansion, but does not pretend to be ideal.

My tables give a temperature of 417 F for a saturated water substance at 300 psi.

So there is your temperature.

To calculate the expansion % after bursting, the table gives the specific volume of the water at this temperature and pressure as 0.018896 cuft /lb and for vapour

1.5442 cuft / lb.

You would have to decide if you are going to say all the water turns to steam on release at bursting.

Then the ration of these two figures will give the expansion %

But the question is asking for a fractional increase (%) in volume just before rupture. Won't that be a Sat. mixture. And if I need to find the exergy just before rupture, won't it be Saturated mixture internal energy values also?

Not just before rupture.How do determine the temperatureand the fractional increase in volume (%)at the time ofrupture

I don't know if you copied the exact words of the question (or all of it), but It was poorly phrased an open to interpretation.

@studiotNot just before rupture.

I don't know if you copied the exact words of the question (or all of it), but It was poorly phrased an open to interpretation.

Assume a 55 gal. hot water heater is initially filled with liquid water at dead state conditions (14.7 psia, 75 °F). The contents are then heated until the tank ruptures at 300 psia. Determine:

Attacheded is a short form steam table.

At 1atm it says the specific volume is 0.01672 cuft/lb

At 300psi it gives .018890 cuft/lb and a temperature of 417F

So the % increase in volume of water is (.01890 - .01672) / .01672 *100 % which is about 13%.

Can you read the energy table of the water under these conditions and complete the last part ?

You will need to convert 55 gals to lbs (US gals I presume) to get total energy as asked for

This is why UK gallons were better than US ones - a little ditty I learned in primary school

A pint of pure water

weighs a pound and a quarter

So a UK gallon weighs 10 lbs.