The speed at its border is of 50 m/s.

When we cut the power, it takes the saw 8 seconds to completely immobilize with a constant deceleration.

**How many turns has the saw done before it completely stopped?**

I did :

c = 2*pi*0.25m = 1.57m

x = 1/2 * (50m/s + 0m/s) * 8s

The number of turns should be equal to x/c = 200m/1.57m = 127.39 turns

But the answer given by the manual is 3 * 127.39 = 382 turns

What have I done wrong to be short by a factor of 3? Or is it just the manual that is wrong? Because I've looked every possible avenue and can't find what isn't right.

Thanks a lot!