Capacitor Question

Feb 2020
3
0
Tacoma, WA
How is the potential difference across a fully charged capacitor related to the capacitance?
 
Apr 2017
541
140
It's not ... and it doesn't matter if it's 'fully charged' or not ...

Potential difference is just voltage ... the voltage across a capacitor is it's voltage and unrelated to anything else.
 
Apr 2015
1,233
359
Somerset, England
You have the following relationships available based on the basic one

Q = CV Where Q is the charge on the capacitor, C is the capacitance and V is the votlage across it.

This can be translated to energy, E (Joules) as follows


\(\displaystyle E = \frac{1}{2}C{V^2} = \frac{1}{2}QV = \frac{1}{2}\frac{{{Q^2}}}{C}\)

Does this help?
 
Feb 2020
3
0
Tacoma, WA
You have the following relationships available based on the basic one

Q = CV Where Q is the charge on the capacitor, C is the capacitance and V is the votlage across it.

This can be translated to energy, E (Joules) as follows


\(\displaystyle E = \frac{1}{2}C{V^2} = \frac{1}{2}QV = \frac{1}{2}\frac{{{Q^2}}}{C}\)

Does this help?
awesome thank you!