You have the following relationships available based on the basic one

Q = CV Where Q is the charge on the capacitor, C is the capacitance and V is the votlage across it.

This can be translated to energy, E (Joules) as follows

\(\displaystyle E = \frac{1}{2}C{V^2} = \frac{1}{2}QV = \frac{1}{2}\frac{{{Q^2}}}{C}\)

Does this help?