A large sealed container full of air falls into the ocean. It has internal dimensions of 6.06 2.59 2.43 m, with walls made of steel (8050 kg m3 ) which is 2.00 cm thick. Does it float?

2. Relevant equations

FBuoyancy = density*volume*g

weight = mg

m = density*volume

density of salt water = 1030 kg/m^-3

3. The attempt at a solution

Volume = (6.06)(2.59)(2.43) = 38.139

FBuoyancy = (1030)(38.139)(9.81)

= 385,367.9 N

= 385,000 N

Weight:

Wtot = Wair + Wsteel

Wair = m*g = density*volume*g = (1.29)(38.139)(9.81) = 482.65 N

Wsteel = (8050)(38.139)(.02meters)(9.81) = 60,237.1 N <- I don't understand what to do about the thickness.

Weight = 60,719. 8N which is less than FBuoyancy which means it floats.

Is this right?