So if I divide Fg into components along to the incline, there Is force Fx pushing the box downwards a Fy pushing the wedge. If Fx = m.gx then gx = g.sin 35 = 5,6. (acceleretion of the box) Force Fy Is m.g.cos 35 = 4N. Then force that pushes the wedge Is F= Fy.sin 35 = 2,3N so acceleration of wedge is a = F/ M = 0.6

Is there a mistske?