# Another pulley problem

#### bluemouse

I feel like I got really close for this one. I got theta = 81.5 degrees, but I was wondering, in 2Tsintheta = mg, is m the combined masses? Please help me solve this!

#### Cervesa

working on one side is sufficient to find the tension in the string between A and B ...

$mg = T_2\sin{\theta} \implies T_2 = \dfrac{mg}{\sin{\theta}}$

$T_1 = T_2\cos{\theta} \implies T_1 = \dfrac{mg}{\tan{\theta}}$

topsquark