B bluemouse Dec 2019 13 0 us Dec 9, 2019 #1 I feel like I got really close for this one. I got theta = 81.5 degrees, but I was wondering, in 2Tsintheta = mg, is m the combined masses? Please help me solve this!

I feel like I got really close for this one. I got theta = 81.5 degrees, but I was wondering, in 2Tsintheta = mg, is m the combined masses? Please help me solve this!

Cervesa Jan 2019 55 41 Dec 9, 2019 #2 working on one side is sufficient to find the tension in the string between A and B ... $mg = T_2\sin{\theta} \implies T_2 = \dfrac{mg}{\sin{\theta}}$ $T_1 = T_2\cos{\theta} \implies T_1 = \dfrac{mg}{\tan{\theta}}$ Reactions: topsquark

working on one side is sufficient to find the tension in the string between A and B ... $mg = T_2\sin{\theta} \implies T_2 = \dfrac{mg}{\sin{\theta}}$ $T_1 = T_2\cos{\theta} \implies T_1 = \dfrac{mg}{\tan{\theta}}$