Acceleration of a Mass in a Pulley System

Nov 2016
3
0
Hello everyone I'm new here...
can you help me in this problem
thank you.
 

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Aug 2008
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reference attached diagram for set up of scalar equations ...

$T_1 - m_1g\sin{\theta} = m_1a_1$

$m_2g - T_2 = m_2a_2$

$T_2=2T_1$

$a_2 = 2a_1$

If I solved the system correctly for $a_2$ ...

$a_2 = \dfrac{g(m_2 - 2m_1\sin{\theta})}{m_1+m_2}$
 

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topsquark

Forum Staff
Apr 2008
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On the dance floor, baby!
skeeter got to it before me. Hey, speaking of that, do you carry the zika virus? :)

-Dan
 
Nov 2016
3
0
thanks for your help skeeter but this is not the right
answer... for m2 move downward the pulley should move to the right
hope it will help you find any mistake in your solution
there is a chance that your solution is correct because it's an auto-checker