# A question on physics kinematics

#### Mithilaa

The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find:
A)the time dependence of the velocity and acceleration of the particle

#### Pmb

PHF Hall of Fame
The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find:
A)the time dependence of the velocity and acceleration of the particle
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• 1 person

#### HallsofIvy

Assuming that by "root of x" you mean the square root, $$\displaystyle x^{1/2}$$, "v= a root of x" is $$\displaystyle \frac{dx}{dt}= ax^{1/2}$$. That can be written as $$\displaystyle x^{-1/2}dx= a dt$$. Integrate.

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#### Mithilaa

My doubt is how to integrate
Is it 2* root of x equals to at

#### Pmb

PHF Hall of Fame
I guess hoi thinks the rules don't apply to him.

#### Mithilaa

I actually have the solution of this question but I have some doubts on the question.thats why I asked it

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#### Mithilaa

I am sorry .it was my mistake

#### HallsofIvy

I actually have the solution of this question but I have some doubts on the question.thats why I asked it
In a situation like that, show us, not only what solution you have, but how you got that solution.