A question on physics kinematics

Jul 2018
4
0
The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find:
A)the time dependence of the velocity and acceleration of the particle
 

Pmb

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Boston's North Shore
The velocity of a particle moving in the positive direction I of the x axis varies as v=a*root of x,where a is a +'ve constant .assuming that at moment t=0 the particle was located at the point x=0.find:
A)the time dependence of the velocity and acceleration of the particle
We don't do people's homework for them. Please read the forum rules.
 
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Aug 2010
434
174
Assuming that by "root of x" you mean the square root, \(\displaystyle x^{1/2}\), "v= a root of x" is \(\displaystyle \frac{dx}{dt}= ax^{1/2}\). That can be written as \(\displaystyle x^{-1/2}dx= a dt\). Integrate.
 
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Jul 2018
4
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My doubt is how to integrate
Is it 2* root of x equals to at
 

Pmb

PHF Hall of Fame
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I guess hoi thinks the rules don't apply to him.
 
Jul 2018
4
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I actually have the solution of this question but I have some doubts on the question.thats why I asked it
 
Last edited:
Aug 2010
434
174
I actually have the solution of this question but I have some doubts on the question.thats why I asked it
In a situation like that, show us, not only what solution you have, but how you got that solution.