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Old Jun 19th 2010, 01:37 AM   #1
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Double slit diffraction

Ello,
This is my question,
In a double slit experiment using monochromatic light and two slits 0.50mm apart, it was found that the second dark band was 3.6mm from the centre of the central maximum on teh screen. If th screen was 1.9m from the slits, what was the wavelength of the light used?

I know that I have to use this equation:
x=lambdaL/d

I know these values:
lambda=? (what I need to find)
L=1.9m
d=5*10^-04
But I don't know what x is.
Could someone please help me find the value for x.
Thanks heaps for your help physics help forum.

Last edited by Awsom Guy; Jun 19th 2010 at 01:38 AM. Reason: sorry i stuffed up latex for lambda
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Old Jun 19th 2010, 03:52 AM   #2
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What is 3.6mm?
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Old Jun 20th 2010, 12:58 AM   #3
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don't worry I got the answer, btw 3.6mm is the inteference thing as in the dark band and bright band thing. thus w=3.6 * 3/2. The equation there is wrong this is the right equation w=lambdax/D
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