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Old May 1st 2011, 11:18 AM   #1
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Final Temperature of mercury

I am stumped as to how to properly solve the second part of the following problem. I was able to solve the first part, but am in need of assistance for part "b". Thanks!!

here is part a:

How much heat is required to raise the temperature of 0.250 of water from 20.0 to 30.0?
Using the formula

Q = m * specific heat of water * delta T

= .250 * 4.19E3 *10
Q = 10475 J

part b is as follows:

If this amount of heat is added to an equal mass of mercury that is initially at 20.0, what is its final temperature?

Here is what I did:

Q = .250 * 18e-5* (change in T)
Q = 4.5e-5 (T(final) - 20)

10475 = 4.5e-5 * T final - .0009

T final = 2.33e8 which was incorrect

Am i using the wrong equation?

Thanks again!
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Old May 1st 2011, 11:44 AM   #2
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Originally Posted by pre pt marc View Post
I am stumped as to how to properly solve the second part of the following problem. I was able to solve the first part, but am in need of assistance for part "b". Thanks!!

here is part a:

How much heat is required to raise the temperature of 0.250 of water from 20.0 to 30.0?
Using the formula

Q = m * specific heat of water * delta T

= .250 * 4.19E3 *10
Q = 10475 J

part b is as follows:

If this amount of heat is added to an equal mass of mercury that is initially at 20.0, what is its final temperature?

Here is what I did:

Q = .250 * 18e-5* (change in T)
Q = 4.5e-5 (T(final) - 20)

10475 = 4.5e-5 * T final - .0009

T final = 2.33e8 which was incorrect

Am i using the wrong equation?

Thanks again!
Haven't I already suggested you use units on your numbers? If I haven't then please do so.

Your specific heat for Mercury is waaaaaay off. See here.

-Dan
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