I am stumped as to how to properly solve the second part of the following problem. I was able to solve the first part, but am in need of assistance for part "b". Thanks!!

here is part a:

**How much heat is required to raise the temperature of 0.250 of water from 20.0 to 30.0?** **Using the formula**

Q = m * specific heat of water * delta T

= .250 * 4.19E3 *10

Q = 10475 J

part b is as follows:

If this amount of heat is added to an equal mass of mercury that is initially at 20.0

, what is its final temperature?

**Here is what I did:**

Q = .250 * 18e-5* (change in T)

Q = 4.5e-5 (T(final) - 20)

10475 = 4.5e-5 * T final - .0009

T final = 2.33e8 which was incorrect

Am i using the wrong equation?

Thanks again!