**Heat Engines**
For the first question, since the process is described as adiabatic, you can use the first and last points on the curve and solve for gamma. i.e. PV^(Gamma)=const. Solve for Gamma using points P0,V0 and P0/32,8V0. i.e 32*(1/8)^Gamma=1.
(1/8)^Gamma=1/32. 8=2^3, 32 = 2^5 Therefor gamma must equal 5/3 the value of which means it is a monoatomic gas. If it was diatomic, gamma would be about 1.4 (7/5). Heat capacity can be expressed as f +2 / f where f is the amount of degrees of freedom of the gas molecule. Monoatomic gases have three degrees of freedom therefor gamma is 5/3. |