The

pressure in a section of horizontal pipe with a diameter of 2.00 cm is 147 kPa. Water flows through the pipe at 2.40 L/s. If the pressure at a certain point is to be reduced to 101 kPa by constricting a section of the pipe, what should the diameter of the constricted section be?

Using Bernoulli’s Equation, and setting density to 1000 kg * m^3 (the density to water), velocity should be 9.887 L/S. Then plugging in the values to V1*A1 = V2 * A2 I found what the cross section area should be for the constricted section, and then determined what the diameter should be. That did not give me the answer.

Submission # Try Submitted Answer

1 Incorrect. (Try 1) 3.93 cm

2 Incorrect. (Try 2) 0.005091 m

3 Incorrect. (Try 3) 16.9 cm

4 Submission not graded. Use more digits. 0.0012 cm

5 Incorrect. (Try 4) 0.00118 m

6 Incorrect. (Try 5) 0.00236 m

7 Incorrect. (Try 6) .236 cm

8 Incorrect. (Try 7) 0.985 cm

9 Incorrect. (Try 8) 2.00 cm

10 Submission not graded. Use more digits. 1.9 cm

11 Incorrect. (Try 9) 1.90 cm

12 Incorrect. (Try 10) 1.65 cm

13 Incorrect. (Try 11) 1.66 cm