Thermodynamics and Fluid Mechanics Thermodynamics and Fluid Mechanics Physics Help Forum Apr 24th 2009, 09:36 AM #1 Junior Member   Join Date: Apr 2009 Location: California Posts: 2 How much energy can carbon dioxide emit? What is the maximum energy that a carbon dioxide molecule can emit in joules per second?    Apr 24th 2009, 03:30 PM #2 Senior Member   Join Date: Apr 2008 Posts: 815 That's a rather vague question or a question without a precise answer. As an approximation we can consider such a molecule as a rigid body with 6 degrees of liberty. So $\displaystyle E=\frac{mv^2}{2}+\frac{I\omega ^2}{2}$. So it's like asking what is the maximal velocity such a molecule can have. I'm pretty sure that for high speeds the formula I gave is not valid. I might be wrong about everything though. Otherwise I would just use $\displaystyle E=mc^2$ __________________ Isaac If the problem is too hard just let the Universe solve it.   Apr 24th 2009, 10:00 PM   #3
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 Originally Posted by arbolis That's a rather vague question or a question without a precise answer. As an approximation we can consider such a molecule as a rigid body with 6 degrees of liberty. So $\displaystyle E=\frac{mv^2}{2}+\frac{I\omega ^2}{2}$. So it's like asking what is the maximal velocity such a molecule can have. I'm pretty sure that for high speeds the formula I gave is not valid. I might be wrong about everything though. Otherwise I would just use $\displaystyle E=mc^2$ Thanks for your reply. I suppose I should have put the question this way: What is the maximum IR radiation that a CO2 molecule can absorb, and from that energy, what is the maximum energy it can emit?   Apr 25th 2009, 06:53 AM   #4
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 Originally Posted by williampinn Thanks for your reply. I suppose I should have put the question this way: What is the maximum IR radiation that a CO2 molecule can absorb, and from that energy, what is the maximum energy it can emit?
Oh... I'm sure it deals with quantum mechanics. My knowledge is too limited for now to answer this question. So I'll let other help you on this. Clearly the question is much more precise now.
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