Physics Help Forum Thermal Equilibrium Question

 Thermodynamics and Fluid Mechanics Thermodynamics and Fluid Mechanics Physics Help Forum

 Feb 11th 2019, 05:19 PM #1 Junior Member   Join Date: Feb 2019 Posts: 1 Thermal Equilibrium Question 2kg of ice is at -10°C is mixed with 15kg of water at 25°C. What is the final temp when equilibrium is achieved. Q = Energy M = mass c = Heat capacity ∆T = Change in temperature W = Water I = Ice Heat capacity for water is 4200 J/Kg Heat capacity for Ice is 2100 J/Kg Well, i approached this question by first finding: Q Of water (lost) = Q Of Ice (Gained) Q=M(w) x C(w) x ∆T(w) --> 15 x 4200 x (25 - T) ... = 63000(25-T) [T here is temperature equilibrium] Ice would be 2 x 2100 x{i don't know what to insert here} Note: I think the ice is also melting and requires some latent heat of fusion. Which was [Fusion heat] = 3.34 x 10^5 J/Kg. I'm just lost at this point from the ice ∆T. Any suggestions what to do at that stage? Last edited by IshaanM8; Feb 11th 2019 at 05:20 PM. Reason: Comma errors
 Feb 13th 2019, 10:27 AM #2 Senior Member   Join Date: Jun 2010 Location: NC Posts: 419 Hi, This is a clasic problem. The usual approach is to taking the two masses together as an abiabatic system, the event is called "thermal equilibration." Here is an example: Citris Concentrate topsquark likes this.

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