Physics Help Forum Majic Fountain

 Thermodynamics and Fluid Mechanics Thermodynamics and Fluid Mechanics Physics Help Forum

 Feb 28th 2018, 12:50 PM #1 Senior Member   Join Date: Jun 2010 Location: NC Posts: 412 Majic Fountain I show the initial state then the "in operation." What's the simple answer why this goes? Majic Fountain | THERMO Spoken Here! Thanks, JP topsquark likes this.
 Feb 28th 2018, 06:00 PM #2 Senior Member   Join Date: Apr 2017 Posts: 453 Not quiet sure what this is ... Are you saying this magic fountain runs without an apparent input of energy ??? If so , then the input comes because the reservoir is open to the atmosphere , evaporation will occur cooling the water in A , which is drawn down to C ...the enclosed air C and B will now be colder .. drawing heat from the outside which powers the device ... I guess ! The dryer the outside air , the better it should work . Forget all of the above ... I misread the illustration... It seems you are lifting one of the containers .... well sure you will get some action , you have put some potential energy into the system which is transmitted via changes in pressure in the pipe work.
Mar 13th 2018, 03:36 AM   #3
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 Originally Posted by THERMO Spoken Here I show the initial state then the "in operation." What's the simple answer why this goes? Majic Fountain | THERMO Spoken Here! Thanks, JP
Water from A wants to drop into container B due to the gravitational term of the Bernoulli equation (pressure difference). However, because the bottles are sealed, if water drops from A to B, air is pushed from bottle B to bottle C, forcing water up the tube in bottle C into A. This presumably occurs because the pressure difference is lower between and A and C than it is A and B, so when the air is forced through the tube, the pressure is difference is greater than than the pressure difference between A and C.

You could probably use Bernoulli's equation to get quantitative estimates for things

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