**Bernoullis**
Greetings all,
I am working on a question involving the attached system.
I need to find the head required for the pump and its power requirement assuming 70% efficiency.
I have the following given information:
Pipe Area = 0.00636m^3. Flow(Q)= 0.01m^3/s Average Velocity = 1.57m/s Density of Fluid = 960kg/m^-3. Liquid viscosity = 0.081 Pa/s
I have calculated the head losses using firstly the Equivalent Head (Hm) to be 1.03m and Number Velocity head (Hf) to be 0.54m.
I think I need to use Bernoulli's to work out the power, however I don't fully understand its use and have found several different Power outputs.
Im currently sat with the answer as 2.2Kw.
I have added the height to combat as 15m + 1.57 (total losses)
P2 I have 200000pa/(960x9.81)
This works out as P1 = 356Kpa
Im not sure if this is correct and how to get this into pump power.
Thanks
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Last edited by GSXR750; Apr 23rd 2017 at 11:08 AM.
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