I'm completely stuck
I've been trying to find the temperature of air in an otto cycle before the fuel is ignited. I know
exhaust air is 733^C,
Cp is 1005,
air flow mass rate is 0.00460
fuel mass flow rate is 0.000393.
The cal val for fuel is 46.5 Mj/kg,
and im using the equation Q=m x cv (t3-t2)
but...i just get a ridiculous answer every time.
46.58106 x 0.000393=18 kj/kg
1.225 * 0.00460=0.005635
Q=m x cv (t3-t2)=>(Q/(m x Cv))-t2=-t1
(18 x 103 / (718 x 0.005635))-1006=3442k for the lower temperature,
I'm not sure whats going wrong.
If anyone could shed some light that would be great