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Old Jul 21st 2016, 01:50 PM   #1
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Unhappy Basic problem, quick help needed

Hi, really simple but my head is fried and i can't get my head around this. Would the guage reading at A be as simple as atmospheric pressure+pgh for (ii)?

Basic problem, quick help needed-image.jpg
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Old Jul 21st 2016, 03:17 PM   #2
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The gauge on the right has the column exposed to the air 150 mm below the other column. Therefore, the air pressure in B is 150 mm of mercury below atmospheric pressure. But the gauge on the left shows the entire length of the right arm as 400. What we need to know is how high above the left arm it is.
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Old Jul 21st 2016, 07:45 PM   #3
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Originally Posted by HallsofIvy View Post
The gauge on the right has the column exposed to the air 150 mm below the other column. Therefore, the air pressure in B is 150 mm of mercury below atmospheric pressure. But the gauge on the left shows the entire length of the right arm as 400. What we need to know is how high above the left arm it is.
Has there not been enough information given then?
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