Two comments:
1. You haven't included the area of the two ends of the submarine cylinder.
2. Be careful taking calculations to so many digits of accuracy. You use values for g of 9.81 (3 digits of accuracy), you're given the weight of a bus to only 1 digit, and you rounded off the surface area of the sub to 6283.19 m^2 (6 digits). Hence your answer is accurate to 3 digits at most, not ten digits. So 1.05 x 10^7 London busses is a better answer than 10547142.25 London Buses.
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Last edited by ChipB; Mar 1st 2016 at 03:25 PM.
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