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Old Nov 24th 2015, 01:26 PM   #1
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Air flow over a U-Tube

Hello!

I attached a problem I'm working on for class.

My solution: Look at Bernoulli's equation which is a constant so

Pressure(a) + 1/2 density v(a)^2 +density g h = Pressure(b) + 1/2 density v(b)^2 +density g h

Because b's velocity is greater, a's pressure has to be greater to make the equation equal. Because a's pressure is greater, the force is greater, so the water would rise on a's side and lower on b's side.

Does that seem right?
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Last edited by beika; Nov 24th 2015 at 01:30 PM.
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Old Nov 24th 2015, 02:09 PM   #2
MBW
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Your reasoning is correct, but your answer is wrong!

As you correctly deduced the higher velocity at "b" implies that the air pressure at "a" will be greater than the air pressure at "b".

This means the air pressure pushing down on the water at "a" is greater than the air pressure pushing the water down at "b"

So the water at "a" will be pushed down more than the water at "b"...
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Last edited by MBW; Nov 24th 2015 at 02:11 PM.
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Old Nov 24th 2015, 03:20 PM   #3
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Oh thank you!
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