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Old Apr 17th 2014, 10:25 AM   #1
hwl
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Join Date: Apr 2014
Posts: 1
constant Jacobian transformation of an inertial frame

Suppose we do a constant Jacobian transformation (NOT Lorentz) of an
inertial frame. This defines a non-inertial field with a constant metric in
which the acceleration vector is NON-ZERO. But this directly contradicts
the geodesic - metric equation. According to this equation, the acceleration
vector is ZERO, because the metric is constant and so it has zero partial
derivatives which make the metric connection zero.

Can anyone explain this direct contradiction?
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