Physics Help Forum m=2(1 means light speed)

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 Mar 14th 2017, 11:30 PM #1 Member   Join Date: Jul 2013 Posts: 49 m=2(1 means light speed) 1+1=2 1*m=(1^2)+(1^2) 1*m=2(m=2, m is meter) Every number in formula has 1 as the truth(logical basic) So (1/2)*a*(t^2)=S 2*S=a*(t^2) a*t=c(light speed) t=2*S t=4*x And time means 4 multiply x, so x is relativity number for formula.
 Mar 15th 2017, 03:05 PM #2 Physics Team     Join Date: Jun 2010 Location: Naperville, IL USA Posts: 2,271 For those who may like to see a translation of Philipishin's post, this is what I can make out: $\displaystyle 1+ 1 = 2$ $\displaystyle 1 \times m = 1^2 + 1^2 \ \Rightarrow \ m = 2$ (defining m as 2, I suppose) $\displaystyle \frac 1 2 a t^2 = s \ \Rightarrow \ 2s = at^2$ (standard elementary equation of motion in inertial frames) $\displaystyle at = c$ (c = lightspeed, seems to assume that one can reach c at constant acceleration) $\displaystyle t= 2s$ (have redefined c = 1) $\displaystyle t=4x$ ( i have no idea what x is here) topsquark likes this.
Mar 15th 2017, 07:21 PM   #3

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 Originally Posted by philipishin 1+1=2 1*m=(1^2)+(1^2) 1*m=2(m=2, m is meter) Every number in formula has 1 as the truth(logical basic) So (1/2)*a*(t^2)=S 2*S=a*(t^2) a*t=c(light speed) t=2*S t=4*x And time means 4 multiply x, so x is relativity number for formula.
This starts out reading like a unit conversion, but later on tries to establish an equation in SR. At what point are we going from units to quantities?

And thanks to ChipB for the translation attempt.

-Dan
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Apr 23rd 2017, 04:20 PM   #4
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 Originally Posted by philipishin 1+1=2 1*m=(1^2)+(1^2) 1*m=2(m=2, m is meter) Every number in formula has 1 as the truth(logical basic) So (1/2)*a*(t^2)=S 2*S=a*(t^2) a*t=c(light speed) t=2*S t=4*x And time means 4 multiply x, so x is relativity number for formula.
This is a classic example of playing with numbers and equations with no concerning of the meaning of those equations. Here the OP is using the non-relativistic expression for an accelerating particle and assumes that a particle will reach the speed of light using that expression in the time t, which is fundamentally wrong in all respects. That expression is not generally valid and fails miserably at high speeds.

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