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-   -   First 6 allowed states for an electron in an infinite square well of width 0.2nm (http://physicshelpforum.com/quantum-physics/1729-first-6-allowed-states-electron-infinite-square-well-width-0-2nm.html)

 craka Mar 23rd 2009 03:00 AM

First 6 allowed states for an electron in an infinite square well of width 0.2nm

Hi, just want to check if this is correct.

Question asks to find the first 6 allowed states for an electron in infinite square well of width 0.2nm (Partial answer E1=9.4eV E2=37.6eV)

For an infinite square well En is given by
$\displaystyle E_n = \frac{{n^2 \pi ^2 \hbar ^2 }}{{2mL^2 }}$

I just went that E being proportional to n^2 than E at n=3 would be 3^2 time E3 thus giving 84.6eV and similarly E4=150.4eV , E5=235eV and E6=338.4eV

Or should have this been done differently?

 physicsquest Mar 23rd 2009 03:40 AM

That is perfectly fine except you havent mentioned E2 = 37.6 ev.

 craka Mar 23rd 2009 04:00 AM

Thanks. I didn't mention E2 as it was E1 and E2 were already given.

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