Originally Posted by **oz93666** so ...imagine the ram pushing up perpendicular...every meter the weight is raised , the ram is extended a meter ...
now angle the ram , every meter the load is raised vertically , the ram has extended more than a meter ... this makes it easier on the ram , it can now raise a heavier load ...
if the ram is sloped 60*to the vertical , and the load is only allowed to move vertically then every meter the load is raised the ram is extended 2 meters ... so ram only needs to push half as much , a one tonne ram could raise a 2 tonne load **Cos the angle**
angle of ram 60 to vertical ...cos 60 =0.5 ... a half tonne ram could lift a 1 tonne load
angle of ram 30 to vertical ...cos 30=0.866 ... a 0.866tonne ram could raise a 1 tonne load
angle of ram 0 to vertical ....cos 0 =1 ... a one tonne ram can raise a 1 tonne load |

I particularly chuckled at the last one.

A 1 tonne ram acting horizontally can raise a 1 tonne load vertically.

No way.

Welcome to the forum, Anne.

Firstly never be afraid to ask if you don't know.

Don't guess.

Your ram will have specified maximum and working pressures.

The axial force F exerted by the ram is the product of the piston (bore) area and the pressure.

F = A x P

The pressure developed is only what is needed to lift the given weight, up to the maximum allowed.

You have said that the ram axis is set at 65, but omitted to say whether this is with respect to the horizontal or vertical.

The force exerted by the ram in any direction is given by the formula

force in a specific direction, f = axial force F times cosine of the angle between that direction and the ram axis, a.

f = F cos(a)

This force must be equal to or slightly larger than the weight to be lifted.

So in your case, if 65 is to the horizontal then angle a to the vertical is 25.

One more thing, your weight is 106 kg, which is a unit of mass not force.

The weight is the gravitational force exerted by the Earth on this mass and is equal to 106 times the gravitational constant which is 9.81.

This force is measured in Newtons.

So you have

F x cos(25) = 106 x 9.81

or

F = (106 * 9.81) / cos25

and P is F/A = (106 * 9.81) / A *cos25

Note that the diameter may need converting to metres to get the pressure units correct.