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Old Aug 22nd 2016, 01:06 PM   #1
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The theory of everything

I believe i discovered the theory of everything. But i'm not sure about that. I would like and appreciate any opinion, comment and review for this. You can read and download my research at the following link :

http://www.scribd.com/doc/251000080/The ... Everything

Also i attach my research in pdf file format.
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Old Aug 22nd 2016, 01:55 PM   #2
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Right off the bat I see a glaring error that pervades your work: zero divided by zero is NOT infinity; it's undefined. You can set this by rearranging the equations:

1 x 0 =0 and 2 x 0 = 0

The first can be rearranged to 0/0 = 1, and the second to 0/0= 2. Which one is correct? Well, both are, and neither are. In general whereas dividing a non-zero number by 0 will yield plus or minus infinity, dividing 0 by 0 does not. Consequently all your equations that try to make use of 0/0 = infinity are in error.

Your premise is that the speed of light 'c' is not constant. So you end up talking about situations where E=m^2 yields E = 0 for non-zero values of m Do you have any evidence to back up the idea that c could equal zero?

Last edited by ChipB; Aug 22nd 2016 at 02:04 PM.
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Old Aug 22nd 2016, 02:11 PM   #3
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I'm afraid that there is another basic problem to your approach. Einstein's equation is really (see image below). p is the linear momentum of the object of mass m. So what you worked out only deals with particles that have no momentum, that is, stationary particles. As you say later on that your particles have kinetic energy, this is a contradiction.

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Old Aug 22nd 2016, 11:32 PM   #4
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You might be interested to know your attempt at classifying has been done using irreducible representations of one particle states of the homogeneous Lorentz group. (This is what Special Relativity deals with most of the time.) Don't worry about the terminology here: it sounds worse than it is.

We can categorize different particle states in the following way (which is similar to what you were attempting.)
a) p^2 = -M^2, E > 0
b) p^2 = -M^2, E < 0
c) p^2 = 0, E > 0
d) p^2 = 0, E < 0
e) p^2 = M^2
f) p = 0, E = 0

These list all the different possibilities for particle states. Note that we don't have to use any of these...that's up to experiments to determine. However we can characterize each particle in a very similar fashion to what you were doing.

a) and c) are all we need to characterize known particles. a) is a typical "matter" particle and c) is a stationary (not moving) particle. f) says nothing is there at all and is essentially representing the vacuum.

b) and d) would represent a particle with negative energy. Even anti-matter has positive energy so we have to discard these.

To be perfectly honest I really don't know what e) would be. It has an imaginary mass M so it could represent a tachyon: a particle that travels faster than the speed of light. No such particles have been found and I don't think anyone thinks there will be.

-Dan
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