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Old Jul 26th 2018, 08:21 AM   #1
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X4 Explanation of the μ Hydrogen Phynomenon

X4 Explanation of the μHydrogen Phenomenon
When the electron of a Hydrogen atom is replaced with a μparticle, the atom turns to be μHydrogen. For detailed information, see relevant publications.
There is a phenomenon occurs: the radius of the proton inμHydrogen atom contracted. Why?
Blow we try to use the conclusion in X4 Theory of Photon Ⅲ to explain it.
The radius of the proton in Hydrogen atom is R1 ≈ 8.768×10ˆ-16m, while the radius of the proton inμHydrogen atom is R2 ≈ 8.418×10ˆ-16m.
The mass of an electron is Me ≈ 9.1×10ˆ-31kg, while the mass of aμparticle is Mμ ≈ 200 ×9.1×10ˆ-31kg.
The mass of a proton is Mp ≈ 1.6726×10ˆ-27kg.
The reduced mass of the electron in Hydrogen atom is:
μ1 = Me Mp/ ( Me+ Mp) ≈ (9.1×10ˆ-31) ×(1.6726×10ˆ-27)/ [(9.1×10ˆ-31)+(1.6726×10ˆ-27)] ≈ 9.0951×10ˆ-31kg
The increased mass of the proton in Hydrogen atom is:
M1 = Mp+ Me -μ1 ≈ (1.6726×10ˆ-27)+ (9.1×10ˆ-31)- (9.0951×10ˆ-31) ≈1.6726×10ˆ-27kg
The reduced mass of theμparticle in μHydrogen atom is:
μ2 = Mμ Mp/ ( Mμ+ Mp) ≈ (200×9.1×10ˆ-31) ×(1.6726×10ˆ-27)/ [(200×9.1×10ˆ-31)+(1.6726×10ˆ-27)] ≈ 0.1641×10ˆ-27kg
The increased mass of the proton in μHydrogen atom rise to be :
M2 = Mp+ Mμ –μ2 ≈ (1.6726×10ˆ-27)+ (0.182×10ˆ-27)- (0.1641×10ˆ-27) ≈1.6905×10ˆ-27kg
R1/ R2 ≈(8.768×10ˆ-16)/ (8.418×10ˆ-16) ≈ 1.0416
M2/ M1 ≈(1.6905×10ˆ-27)/ (1.6726×10ˆ-27) ≈ 1.0107
Basically in conformity with the relationship R∝1/M in X4 Theory of Photon Ⅲ.
Conclusion: It’s the rise of the increased mass of the proton leads to the contract of the radius of the proton inμHydrogen atom.

Chen Li Qiang
July, 2018
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Old Jul 26th 2018, 09:41 AM   #2
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Originally Posted by htam9876 View Post
X4 Explanation of the μHydrogen Phenomenon
When the electron of a Hydrogen atom is replaced with a μparticle, the atom turns to be μHydrogen. For detailed information, see relevant publications.
There is a phenomenon occurs: the radius of the proton inμHydrogen atom contracted. Why?
Blow we try to use the conclusion in X4 Theory of Photon Ⅲ to explain it.
The radius of the proton in Hydrogen atom is R1 ≈ 8.768×10ˆ-16m, while the radius of the proton inμHydrogen atom is R2 ≈ 8.418×10ˆ-16m.
The mass of an electron is Me ≈ 9.1×10ˆ-31kg, while the mass of aμparticle is Mμ ≈ 200 ×9.1×10ˆ-31kg.
The mass of a proton is Mp ≈ 1.6726×10ˆ-27kg.
The reduced mass of the electron in Hydrogen atom is:
μ1 = Me Mp/ ( Me+ Mp) ≈ (9.1×10ˆ-31) ×(1.6726×10ˆ-27)/ [(9.1×10ˆ-31)+(1.6726×10ˆ-27)] ≈ 9.0951×10ˆ-31kg
The increased mass of the proton in Hydrogen atom is:
M1 = Mp+ Me -μ1 ≈ (1.6726×10ˆ-27)+ (9.1×10ˆ-31)- (9.0951×10ˆ-31) ≈1.6726×10ˆ-27kg
The reduced mass of theμparticle in μHydrogen atom is:
μ2 = Mμ Mp/ ( Mμ+ Mp) ≈ (200×9.1×10ˆ-31) ×(1.6726×10ˆ-27)/ [(200×9.1×10ˆ-31)+(1.6726×10ˆ-27)] ≈ 0.1641×10ˆ-27kg
The increased mass of the proton in μHydrogen atom rise to be :
M2 = Mp+ Mμ –μ2 ≈ (1.6726×10ˆ-27)+ (0.182×10ˆ-27)- (0.1641×10ˆ-27) ≈1.6905×10ˆ-27kg
R1/ R2 ≈(8.768×10ˆ-16)/ (8.418×10ˆ-16) ≈ 1.0416
M2/ M1 ≈(1.6905×10ˆ-27)/ (1.6726×10ˆ-27) ≈ 1.0107
Basically in conformity with the relationship R∝1/M in X4 Theory of Photon Ⅲ.
Conclusion: It’s the rise of the increased mass of the proton leads to the contract of the radius of the proton inμHydrogen atom.

Chen Li Qiang
July, 2018
I think I've let this go on long enough.

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