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 Apr 23rd 2018, 10:12 AM #1 Member   Join Date: Mar 2018 Location: Xinhui Guangdong Province China Posts: 43 tha mass of photon,a topic of both old and new the mass of a photon ,either the static mass is M0 and the released mass is ∞，or the released mass is hγ and the static mass is zero, (the detailed calculation with Special Relativity omitted),but both are meaningless in physics. If photon has no effective mass, how to explain the Campton efffect. what is the mass of a photon?
 Apr 23rd 2018, 10:54 AM #2 Member   Join Date: Mar 2018 Location: Xinhui Guangdong Province China Posts: 43 M=m0 The answer is : the released photon is in the state of X4 = ∞，and the released mass is equal to the static mass: M = M0= hγ/Cē Chen Li Qiang April ,2018 from Xinhui Guangdong Province, China Last edited by htam9876; Apr 23rd 2018 at 11:00 AM. Reason: supplement
Apr 23rd 2018, 10:55 AM   #3
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 Originally Posted by htam9876 the mass of a photon ,either the static mass is M0 and the released mass is ∞，or the released mass is hγ and the static mass is zero, (the detailed calculation with Special Relativity omitted),but both are meaningless in physics. If photon has no effective mass, how to explain the Campton efffect. what is the mass of a photon?
The inertial mass of a photon is well defined and very meaningul. It has the value given by he m in

p = mv

Since for a photon v = c and since the energy of a photon is related to its momentum by E = pc we have p = E/c. Substitute these back in and get

E/c = mc

pr

E = mc^2

Solve fpr m to get

m = E/c^2

You're thinking of a potons roper mass, not its inertial aka "relativistic" mass.

Watch this video - http://www.newenglandphysics.org/com...an_Guth_01.mp4

 Apr 23rd 2018, 11:10 AM #4 Member   Join Date: Mar 2018 Location: Xinhui Guangdong Province China Posts: 43 the key the key is X4 = ∞, what is the result?
 Apr 23rd 2018, 11:15 AM #5 Senior Member   Join Date: Aug 2010 Posts: 320 That equation, if it is true, says that X4 does not exist. topsquark likes this.
Apr 23rd 2018, 03:06 PM   #6

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 Originally Posted by htam9876 the key is X4 = ∞, what is the result?
It doesn't matter what X4 is. According to SR the only kind of particle that can travel at the speed of light is a massless one. It comes out of the theory very naturally. PMB has given you a derivation of how to find the momentum of such an object, which is all you need for the Compton effect.

-Dan
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 Apr 23rd 2018, 06:25 PM #7 Member   Join Date: Mar 2018 Location: Xinhui Guangdong Province China Posts: 43 widen the title of this thread widen to be hoton, a topic of both old and new. ?
Apr 24th 2018, 03:10 AM   #8

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 Originally Posted by htam9876 the title of this thread widen to be hoton, a topic of both old and new. ?
Yes, but none of your equations seems to have anything to do with a photon! Your X4 idea seems to be nothing more than a rescaling, which wouldn't predict anything that you say that it does.

-Dan
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 Apr 25th 2018, 09:34 AM #9 Member   Join Date: Mar 2018 Location: Xinhui Guangdong Province China Posts: 43 answer I hope that someone could give the answer that is the same with me .(X4 = ∞，what's the result?)
Apr 25th 2018, 09:37 AM   #10
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 Originally Posted by htam9876 I hope that someone could give the answer that is the same with me .(X4 = ∞，what's the result?)
A large number of people who are new to physics and has a new idea hopes the same thing. Nobody has ever been right in that respect.

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