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Old Jun 25th 2012, 06:44 PM   #1
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Gear Crank

Please, I need help on how to make every calculation relating to using a crank to drive two others in such a way that the driver's one complete period will equal to the other's 3 or more periods.

I will also like to know which of the two sets I have uploaded is the most preferable.

thanks.
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Old Jun 26th 2012, 09:10 AM   #2
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The calculation is simply that the radius and circumference of the drive gear (or drive pulley in the case of the belt drive system) must be 3 times or more greater in size than the driven gears/pulleys. Is there something more specific you have in mind?

As for which system is preferable: it depends. The gear-driven system is more efficient and more reliable (no belt to wear out). But the belt system allows more flexibility in placement of the pulleys. That's why automobiles use a drive belt - it allows the crankshaft to drive the cam shaft without them being immediately next to each other. Same thing with the fan belt that drives the water pump, power steering pump and A/C compressor mounted on the front of the car's engine.
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Old Jun 26th 2012, 04:07 PM   #3
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Originally Posted by ChipB View Post
The calculation is simply that the radius and circumference of the drive gear (or drive pulley in the case of the belt drive system) must be 3 times or more greater in size than the driven gears/pulleys. Is there something more specific you have in mind?

As for which system is preferable: it depends. The gear-driven system is more efficient and more reliable (no belt to wear out). But the belt system allows more flexibility in placement of the pulleys. That's why automobiles use a drive belt - it allows the crankshaft to drive the cam shaft without them being immediately next to each other. Same thing with the fan belt that drives the water pump, power steering pump and A/C compressor mounted on the front of the car's engine.
thanks so much chipB. the information is very useful. I am undertaking my final year project in school and I am researching on a self-powered generator whereby the generator produces the needed power to generate. i hope you understand me? I wish to use a motor to drive two generators, one to be serving the motor and the other for output. there are other electronics circuits involved. I will appreciate any information from your wealth of experience. thanks.
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Old Jun 27th 2012, 10:07 AM   #4
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Self-powered generator? You mean you're trying to build a perpetual-motion machine? Good luck with that. Obviously the power produced by the generator will be less than the power required to run the motor that's driving that generator.

Last edited by ChipB; Oct 25th 2013 at 06:35 AM.
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Old Oct 31st 2012, 09:08 PM   #5
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Second law of thermodynamics violation!!!
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Old Oct 25th 2013, 03:25 AM   #6
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Thanks for info.
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Old Oct 3rd 2014, 10:49 PM   #7
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The angular velocity is expressed in radians per second. One revolution = 2 pi radians, so the angular speed is 2 pi radians/12 seconds. The formula that you should remember is w = 2 pi/T, where w = angular velocity in radians/second and T = period of revolution.
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