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Old Nov 19th 2010, 10:59 AM   #11
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Oh you're right, I placed the '2' inside the brackets while it should be outside.

WD = F.s

WD = Fr(theta)

T = Fd; d = 2r, so, T = 2Fr, and F = T/(2r)

Pt = (T/2) x angular displacement

T = (Pt x 2)/angular displacement = (5000 * 300 * 2)/1200pi = 796 Nm
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Old Nov 30th 2010, 06:20 PM   #12
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Originally Posted by Unknown008 View Post
e) I would think that on the motor, there are two ropes acting on it, and hence, the torque is Fd where d is the diameter... =/

Then, in this line:

You used the angular velocity instead of the angular displacement and the radius instead of the diameter.

Torque = 1500000/(1200pi * 2) = 796 Nm

Using what I was saying,

v = r(omega) = 0.15 * (120*2pi/60) = 3pi/5

5000 = F(3pi/5)
F = 2650 N

Fd = T
T = 2650 x 0.3 = 796 Nm
Two ropes???

For constant speed, v, P=Fv.

For constant angular velocity, P=(torque)(angular velocity).

Torque=(5000 Watts)/(4pi rad/s)=398 Nm.
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