calculation frequency of oscillation.
A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation?
2. Relevant equations
n(frequency)=2pi(K/m)^1/2
3. The attempt at a solution
F= dU/dx . given is potential field. so dU/dx= (2*50x +0)=100x. equating it with Kx(since F= Kx) , K=100. so omega(angular frequency)=(K/m)^1/2= (100/10)^1/2= 10^1/2. but the answer as given in the key of my text book is 100^1/2 for angular frequency, hows that possible? where did i go wrong?
