Periodic and Circular Motion Periodic and Circular Motion Physics Help Forum Dec 14th 2016, 03:23 AM #1 Junior Member   Join Date: Dec 2016 Posts: 1 calculation frequency of oscillation. A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation? 2. Relevant equations n(frequency)=2pi(K/m)^1/2 3. The attempt at a solution F= -dU/dx . given is potential field. so dU/dx= (2*50x +0)=-100x. equating it with -Kx(since F= -Kx) , K=100. so omega(angular frequency)=(K/m)^1/2= (100/10)^1/2= 10^1/2. but the answer as given in the key of my text book is 100^1/2 for angular frequency, hows that possible? where did i go wrong?   Dec 14th 2016, 05:44 AM   #2
Physics Team

Join Date: Jun 2010
Location: Morristown, NJ USA
Posts: 2,344
 Originally Posted by harini A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation?

Note that the potential V is given in units of erg/gram. So for a mass of 10 grams the potential is $\displaystyle V = 10(50 x^2 + 100)$ erg, and $\displaystyle \frac {dV}{dx} = 10(100x)$ erg/m.

Last edited by ChipB; Dec 14th 2016 at 05:46 AM.  Tags calculation, frequency, oscillation Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Physics Forum Discussions Thread Thread Starter Forum Replies Last Post Fizzle Periodic and Circular Motion 4 Jul 12th 2014 02:09 AM mattyc33 Electricity and Magnetism 1 Sep 28th 2012 10:02 AM gregade Advanced Mechanics 1 Jun 27th 2012 10:10 AM Bluekitten Advanced Mechanics 1 Nov 12th 2009 11:00 PM dsptl Advanced Mechanics 1 Nov 9th 2008 01:57 PM