Physics Help Forum Determine the banking angle needed to make a high-speed turn off a highway exit ramp
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 Jul 15th 2014, 11:24 PM #1 Junior Member   Join Date: Jul 2014 Posts: 5 Determine the banking angle needed to make a high-speed turn off a highway exit ramp Determine the banking angle needed to make a high-speed turn off a highway exit ramp with a radius of 720 m if the vehicle is travelling at 80 km/h. Assume there is no friction.
 Jul 16th 2014, 04:48 AM #2 Physics Team     Join Date: Jun 2010 Location: Morristown, NJ USA Posts: 2,336 Set up an equation for the component of acceleration due to gravity that is acting in the direction parallel to the banked road and set it equal to the component of centripetal acceleration also in the direction of the banked road (in the opposite direction). Then solve for the angle.
 Jul 16th 2014, 10:48 AM #3 Junior Member   Join Date: Jul 2014 Posts: 5 mv^2/r=mg ?
 Jul 16th 2014, 11:17 AM #4 Physics Team     Join Date: Jun 2010 Location: Morristown, NJ USA Posts: 2,336 No. Mv^2/R is the centripetal force acting outwards, whereas mg is the gravitational force acting downwards. You need to break both of these into components parallel to and normal to the inclined road. To keep the car on track you want the components of these two forces that act parallel to the road surface to be equal. Hint: it involves sines and cosines of the banking angle. Last edited by ChipB; Jul 16th 2014 at 01:32 PM.
 Jul 16th 2014, 11:47 AM #5 Junior Member   Join Date: Jul 2014 Posts: 5 im sorry im still really confused. would u b able to tell me what exact equation nor formula to use i have to hand in this assignment today and im stresing out!
 Jul 16th 2014, 01:45 PM #6 Physics Team     Join Date: Jun 2010 Location: Morristown, NJ USA Posts: 2,336 Maybe this picture will help: note how the force of gravity and centripetal acceleration both have components that are along the angle of the banking - set them equal and solve for theta. Attached Thumbnails   Last edited by ChipB; Jul 16th 2014 at 01:54 PM.

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