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Old Jul 15th 2014, 11:24 PM   #1
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Smile Determine the banking angle needed to make a high-speed turn off a highway exit ramp

Determine the banking angle needed to make a high-speed turn off a highway exit ramp with a radius of 720 m if the vehicle is travelling at 80 km/h. Assume there is no friction.
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Old Jul 16th 2014, 04:48 AM   #2
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Set up an equation for the component of acceleration due to gravity that is acting in the direction parallel to the banked road and set it equal to the component of centripetal acceleration also in the direction of the banked road (in the opposite direction). Then solve for the angle.
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Old Jul 16th 2014, 10:48 AM   #3
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mv^2/r=mg ?
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Old Jul 16th 2014, 11:17 AM   #4
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No. Mv^2/R is the centripetal force acting outwards, whereas mg is the gravitational force acting downwards. You need to break both of these into components parallel to and normal to the inclined road. To keep the car on track you want the components of these two forces that act parallel to the road surface to be equal. Hint: it involves sines and cosines of the banking angle.

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Old Jul 16th 2014, 11:47 AM   #5
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im sorry im still really confused. would u b able to tell me what exact equation nor formula to use i have to hand in this assignment today and im stresing out!
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Old Jul 16th 2014, 01:45 PM   #6
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Maybe this picture will help: note how the force of gravity and centripetal acceleration both have components that are along the angle of the banking - set them equal and solve for theta.
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Determine the banking angle needed to make a high-speed turn off a highway exit ramp-banking.jpg  

Last edited by ChipB; Jul 16th 2014 at 01:54 PM.
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