Physics Help Forum Activity versus Activity concentration

 Nuclear and Particle Physics Nuclear and Particle Physics Help Forum

 Oct 15th 2010, 07:18 AM #1 Junior Member   Join Date: Oct 2010 Posts: 1 Activity versus Activity concentration Hello all, First i would like to thank you for the time in helping me. I have a Radium source with an activity of 100 Bq, I place the source in a sealed stainless steel cylindrical container of volume 0.00407 m3 for 10 days to measure the buildup of radon in it and i can calculate the activity of radon after 10 days from the equation A(R) =A(Ra)*(1-exp(-L(R)*t). How do i know i measure the activity concentration of the radon inside the cylinder. The activity of the radon after 10 days will be 79 Bq and what would be the activity concentration of the gas formed. Thanks, swethik
 Oct 16th 2010, 01:09 AM #2 Senior Member   Join Date: Mar 2010 Location: Lithuania Posts: 105 Your activity is A(R) =A(Ra)*(1-exp(-L(R)*t). For t=0 A=0 - this is not true. The formula must give A(t=0)=100 A(t=10 days)=79. Please find T=1/L which gives more physical sence.

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