A reactor is producing nuclear energy at the rate of 30000KW.How many atoms of U235 undergo fission per second?How many kg of U235 would be used up in 1000 hr of operation.Assume an energy of 200 Mev is released per fission.(Avogadro number=6*10^26 atom/kg)
Mev = million electron volts ; convert to J . Let this be E joules.
30000 / E will give you the number of fissions per second.
(30000 / E ) x 1000 x 60 x 60 fissions will be required for 1000 hrs of
operation.
The mass of U235 required will be
[(30000 / E ) x 1000 x 60 x 60 ] / 6*10^26 .
